x^2=(x+2)(x+2)-80

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Solution for x^2=(x+2)(x+2)-80 equation: 


Simplifying
x2 = (x + 2)(x + 2) + -80

Reorder the terms:
x2 = (2 + x)(x + 2) + -80

Reorder the terms:
x2 = (2 + x)(2 + x) + -80

Multiply (2 + x) * (2 + x)
x2 = (2(2 + x) + x(2 + x)) + -80
x2 = ((2 * 2 + x * 2) + x(2 + x)) + -80
x2 = ((4 + 2x) + x(2 + x)) + -80
x2 = (4 + 2x + (2 * x + x * x)) + -80
x2 = (4 + 2x + (2x + x2)) + -80

Combine like terms: 2x + 2x = 4x
x2 = (4 + 4x + x2) + -80

Reorder the terms:
x2 = 4 + -80 + 4x + x2

Combine like terms: 4 + -80 = -76
x2 = -76 + 4x + x2

Add '-1x2' to each side of the equation.
x2 + -1x2 = -76 + 4x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = -76 + 4x + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
0 = -76 + 4x + 0
0 = -76 + 4x

Solving
0 = -76 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
0 + -4x = -76 + 4x + -4x
Remove the zero:
-4x = -76 + 4x + -4x

Combine like terms: 4x + -4x = 0
-4x = -76 + 0
-4x = -76

Divide each side by '-4'.
x = 19

Simplifying
x = 19

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